HAMMING DISTANCIA ENTRE DOS CUERDAS

Te dan dos cadenas de igual longitud, tienes que encontrar el Distancia de Hamming entre estas cuerdas.
Donde la distancia de Hamming entre dos cadenas de igual longitud es el número de posiciones en las que el carácter correspondiente es diferente.

Ejemplos:

Input : str1[] = 'geeksforgeeks' str2[] = 'geeksandgeeks' Output : 3 Explanation : The corresponding character mismatch are highlighted. 'geeks  for  geeks' and 'geeks  and  geeks' Input : str1[] = '1011101' str2[] = '1001001' Output : 2 Explanation : The corresponding character mismatch are highlighted. '10  1  1  1  01' and '10  0  1  0  01'

Este problema se puede resolver con un enfoque simple en el que atravesamos las cadenas y contamos la discrepancia en la posición correspondiente. La forma extendida de este problema es editar distancia.

Algoritmo:

int hammingDist(char str1[] char str2[]) { int i = 0 count = 0; while(str1[i]!='') { if (str1[i] != str2[i]) count++; i++; } return count; }

A continuación se muestra la implementación de dos cadenas.

C++

// C++ program to find hamming distance b/w two string #include    using namespace std; // function to calculate Hamming distance int hammingDist(string str1 string str2) {  int i = 0 count = 0;  while (str1[i] != '') {  if (str1[i] != str2[i])  count++;  i++;  }  return count; } // driver code int main() {  string str1 = 'geekspractice';  string str2 = 'nerdspractise';  // function call  cout << hammingDist(str1 str2);  return 0; } // This code is contributed by Sania Kumari Gupta (kriSania804)

// C program to find hamming distance b/w two string #include  // function to calculate Hamming distance int hammingDist(char* str1 char* str2) {  int i = 0 count = 0;  while (str1[i] != '') {  if (str1[i] != str2[i])  count++;  i++;  }  return count; } // driver code int main() {  char str1[] = 'geekspractice';  char str2[] = 'nerdspractise';  // function call  printf('%d' hammingDist(str1 str2));  return 0; } // This code is contributed by Sania Kumari Gupta // (kriSania804)

Java

// Java program to find hamming distance b/w two string class GFG {  // function to calculate Hamming distance  static int hammingDist(String str1 String str2)  {  int i = 0 count = 0;  while (i < str1.length()) {  if (str1.charAt(i) != str2.charAt(i))  count++;  i++;  }  return count;  }  // Driver code  public static void main(String[] args)  {  String str1 = 'geekspractice';  String str2 = 'nerdspractise';  // function call  System.out.println(hammingDist(str1 str2));  } } // This code is contributed by Sania Kumari Gupta // (kriSania804)

Python3

# Python3 program to find  # hamming distance b/w two  # string  # Function to calculate # Hamming distance  def hammingDist(str1 str2): i = 0 count = 0 while(i < len(str1)): if(str1[i] != str2[i]): count += 1 i += 1 return count # Driver code  str1 = 'geekspractice' str2 = 'nerdspractise' # function call  print(hammingDist(str1 str2)) # This code is contributed by avanitrachhadiya2155

// C# program to find hamming  // distance b/w two string using System; class GFG {   // function to calculate  // Hamming distance static int hammingDist(String str1   String str2) {  int i = 0 count = 0;  while (i < str1.Length)  {  if (str1[i] != str2[i])  count++;  i++;  }  return count; }  // Driver code  public static void Main () {  String str1 = 'geekspractice';  String str2 = 'nerdspractise';  // function call  Console.Write(hammingDist(str1 str2)); } } // This code is contributed by nitin mittal

PHP

 // PHP program to find hamming distance b/w  // two string // function to calculate // Hamming distance function hammingDist($str1 $str2) { $i = 0; $count = 0; while (isset($str1[$i]) != '') { if ($str1[$i] != $str2[$i]) $count++; $i++; } return $count; } // Driver Code $str1 = 'geekspractice'; $str2 = 'nerdspractise'; // function call echo hammingDist ($str1 $str2); // This code is contributed by nitin mittal. ?>

JavaScript

<script> // JavaScript program to find hamming distance b/w // two string // function to calculate Hamming distance function hammingDist(str1 str2) {  let i = 0 count = 0;  while (i < str1.length)  {  if (str1[i] != str2[i])  count++;  i++;  }  return count; } // driver code  let str1 = 'geekspractice';  let str2 = 'nerdspractise';  // function call  document.write(hammingDist (str1 str2)); // This code is contributed by Manoj. </script>

Producción

Complejidad del tiempo: O (n)

Nota: Para la distancia de Hamming de dos números binarios, simplemente podemos devolver un recuento de bits establecidos en XOR de dos números.

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Hamming Distancia entre dos cuerdas